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L21 QFT, Quantum Phase Estimation, Shor's Algorithm

Quantum Computing, TCAD, Semicond by Hiu-Yung Wong · 1:14:17 · Watch on YouTube

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Overview

Hiu-Yung Wong connects the Quantum Fourier Transform (QFT) to Quantum Phase Estimation (QPE), showing how controlled phase gates and inverse QFT recover the phase of a unitary eigenvalue. He then introduces Shor's algorithm as a way to factor integers by finding the period of modular exponentiation, using N = 21 and a = 11 to demonstrate a period of 6 and explain the implications for RSA and post-quantum cryptography.

Key takeaways

Chapters

0:00 QFT Circuit Structure and Roots-of-Unity Phase Gates
4:00 Reading the Three-Qubit QFT Circuit
9:09 QFT of |000⟩ and Uniform Measurement Outcomes
12:09 QFT Sign Conventions Across Textbooks
16:34 QFT Gate Count, Parallelism, and Interference
21:17 Unitary Eigenvalues Have Phase Form
30:08 QPE Example: Eigenphases of the Pauli-Z Gate
33:48 Controlled Powers, Phase Kickback, and QPE Precision
37:22 General n-Qubit QPE Circuit
49:22 RSA Encryption and the Integer-Factorization Problem
50:00 Shor's Algorithm and Quantum Factoring
54:43 Post-Quantum Cryptography and Harvest-Now, Decrypt-Later
1:00:08 Factoring as Period Finding for Modular Exponentiation
1:05:12 Worked Period Example: 11^x mod 21

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Transcript excerpt

0:07 to what it look like. You have n cubits from LSP to MSP. Each of them will get a harajama gate like this. And at the end you have a swap gate, n cubit swap gate. And what is so special is that for each of these cubits you will receive a control phase shift gate for the less significant cubit. For example, the second cubit will receive this control phase shift gate. The third cubit will receive one from the least significant, one from the next least significant uh cubit and they all phase shift gate control phase shift. And what is the angle they try to shift?

0:58 If you look at it, it actually is easy to understand. It is omega, the n root of unity. And this omega of course depends on what is the capital n. Now you can think in this way here. This one control this one. So you have 2 cubits. So it's n = 4 2 power two. Right? So you receive a -2 pi / 2 ^ 2. This one is the first cubit. You include you get entangle right? Or you have control it with another two cubit. So it is three cubit system. Capital n is three uh is 8 to the^ 8 to ^ 3 which is 8 and you will receive two one is -2i / n and

1:47 other is -2i / n * 2 okay so for the last one naturally you can expect I'm going to do the phase shift of the n fluid of unity of 2 to power n cubit because it's and handle mine throughout the whole system right and I am going to receive the control facility from each of the less silicon cubit from me so there are n minus one of them right so naturally

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