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Gen Chem_Ch 6_9th_Photoelectric Effect (2)

Dr. Reza Latifi at Oklahoma State University, OSU · 10:44 · Watch on YouTube

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Overview

Dr. Reza Latifi applies the photoelectric equation to 400 nm light, converting wavelength to 4.00 × 10⁻⁷ m and calculating photon energy as 4.97 × 10⁻¹⁹ J. The worked calculation uses a 2 eV work function and obtains a maximum electron kinetic energy of about 1.76 × 10⁻¹⁹ J, although the problem is initially stated with a 1.2 eV work function; with 1.2 eV, the kinetic energy would instead be about 3.05 × 10⁻¹⁹ J.

Key takeaways

Chapters

0:00 Photoelectric Effect Setup and Converting the 400 nm Wavelength
3:30 Photon Energy, Work Function, and Maximum Electron Kinetic Energy
7:30 Doubling Light Intensity Raises Electron Count, Not Kinetic Energy

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Transcript excerpt

0:11 [music] >> Hello and welcome back and thank you very much for watching another lecture from general chemistry. I want to practice one more question about photoelectric effect. They gave me a metal that they say work function for it or binding energy is 1.2 electron volt and then the light that we are sending it has wavelength equal to 400 nanometer. First the question it says are we going to have any electron ejected from the system? Calculate the maximum kinetic energy of the emitted electron and what's going to happen if we you know let's say it says what happened to the number of maximum kinetic energy of emitted electrons if we if the light intensity doubled? Light

0:59 intensity, okay? Not the wavelength or frequency. So, highlight that one and we're going to come after it. Okay, light intensity, not the wavelength or frequency. And so, in order to answer all this question, we need to know what's the binding energy in joule and also how what the energy that we are applying in joule or you can you know use both of them in electron volt. It doesn't matter and but in any case you need to have the same units. So, I go the binding energy or fee Okay. It is given as equal to two electron volt and one electron volt is equal to 1.6

1:47 02 * 10 to the power of minus 19 joule. And I'm going to remind you that the energy the total energy that we are applying is equal to fee plus the kinetic energy. Or you can say the here the kinetic energy or just simply say K. And uh they give us the wavelength for the emitted for light wavelength for the light that we are applying and uh

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Related notes

Summary, takeaways, and chapters were generated by AI from the video's transcript and may contain errors. The video belongs to its creator, Dr. Reza Latifi at Oklahoma State University, OSU.

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