Finding the "volume" of a 4d sphere
Watch on YouTube →
Overview
blackpenredpen derives the 4D hypersphere’s volume by integrating over the solid defined by x² + y² + z² + w² ≤ R². After integrating over w, the calculation uses ordinary 3D spherical coordinates and evaluates the remaining radial, angular, and polar integrals to obtain V = (π²/2)R⁴.
Key takeaways
- The solid 4D hypersphere of radius R is described by x² + y² + z² + w² ≤ R², and its volume is calculated by integrating 1 over that four-dimensional region.
- Integrating first with respect to w reduces the quadruple integral to a three-dimensional integral whose integrand includes 2√(R² − x² − y² − z²).
- Ordinary 3D spherical coordinates handle the remaining x, y, z variables, with Jacobian ρ² sin φ and limits ρ ∈ [0, R], θ ∈ [0, 2π], and φ ∈ [0, π].
- The radial integral requires the substitution ρ = R sin t and evaluates to πR⁴/8.
- The angular factors contribute 2π × 2, producing the final 4D volume formula V = (π²/2)R⁴.
Chapters
0:00
Setting Up the 4D Hypersphere and Quadruple Integral
- Defines a 4D sphere of radius R by x² + y² + z² + w² = R², with the solid interior described by ≤ R².
- Extends the familiar 3D sphere equation x² + y² + z² = R² by adding the fourth coordinate w.
- Sets the volume calculation up as a quadruple integral of 1, integrating in the order dw dz dy dx.
3:00
Integrating Over w and Switching to 3D Spherical Coordinates
- Bounds w between −√(R² − x² − y² − z²) and +√(R² − x² − y² − z²), so integrating w produces a factor of 2√(R² − x² − y² − z²).
- Recognizes the remaining x, y, z region as a 3D ball and uses spherical coordinates with ρ² = x² + y² + z².
- Uses the 3D spherical-coordinate Jacobian ρ² sin φ, with limits ρ from 0 to R, θ from 0 to 2π, and φ from 0 to π.
- Separates the integral into a radial factor, ∫₀ᴿ 2ρ²√(R² − ρ²) dρ, and angular factors ∫₀²π dθ and ∫₀π sin φ dφ.
8:00
Evaluating the Integrals to Derive the Hypersphere Volume
- Evaluates the radial integral with the trigonometric substitution ρ = R sin t, changing the bounds to t = 0 through π/2.
- Simplifies the radial expression to 2R⁴∫₀^{π/2} sin²t cos²t dt, which equals πR⁴/8.
- Evaluates the angular integrals as 2π for θ and 2 for φ.
- Multiplies the factors to obtain the 4D hypersphere volume V = (π²/2)R⁴.
Summary, takeaways, and chapters were generated by AI from the video's transcript and may contain errors. The video belongs to its creator, blackpenredpen.