Dynamics, Lectures 9 & 10: Oxford Mathematics 1st Year Student Lecture
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Overview
Oxford Mathematics lectures 9 & 10 explore constrained motion, starting with the classic Atwood machine problem posed by Charles Dodgson (Lewis Carroll) and analyzing pendulum dynamics, including equilibrium, stability, and energy conservation. The lectures then delve into motion on surfaces of revolution, deriving equations of motion in cylindrical coordinates and demonstrating conservation of angular momentum. Finally, the course introduces Newton's law of gravitation and its application to planetary orbits (the Kepler problem), deriving the central force equation and outlining the mathematical trick using a `u = 1/r` substitution to solve for orbital paths.
Key takeaways
- The period of a simple pendulum, when calculated exactly using energy conservation, involves an elliptic integral, deviating from the simple harmonic motion approximation for larger amplitudes.
- For motion on a surface of revolution, conservation of angular momentum (r^2 * theta_dot = H) arises directly from the axial symmetry and the absence of a theta component in Newton's laws.
- Newton's law of gravitation (F = -GmM/R^2 * R_hat) can be approximated by F = -mg near Earth's surface due to the large ratio of Earth's radius to the height of the object.
- The Kepler problem (planetary orbits under an inverse square central force) can be solved by transforming the radial equation of motion using u = 1/r, leading to a second-order linear ODE in terms of theta: d^2u/d(theta)^2 + u = K/H^2.
Chapters
- Presents a frictionless pulley system with two 100kg masses: one pulled by gravity, the other a monkey.
- Poses the question of what happens when the monkey climbs the rope, highlighting it as a constrained system.
- Introduces Charles Dodgson (Lewis Carroll) as the originator of this problem.
- Reviews pendulum motion as a constrained system with a massless rod.
- Derives Newton's second law in radial and tangential (theta) forms.
- Notes that tension (T) in the rod is determined after solving for the angular motion.
- Identifies two equilibrium points for the pendulum: theta = 0 (stable) and theta = pi (unstable).
- Applies linear stability analysis by perturbing theta around equilibrium points.
- Determines the stable equilibrium (theta=0) has an oscillation frequency of sqrt(g/l).
- States that constraint forces (like rod tension) do no work in this system.
- Defines total energy E as kinetic energy (1/2 M L^2 theta_dot^2) plus potential energy (-MGL cos theta).
- Sets up the conservation of energy equation: E = constant.
- Asks how much initial velocity is needed to swing a pendulum all the way to the top (theta = pi).
- Determines that theta_dot must be non-zero at theta = pi for continuous motion.
- Calculates the minimum energy required: E >= MGL, meaning initial velocity must be sufficient.
- Visualizes potential energy V(theta) = -MGL cos theta as an energy landscape.
- Shows that if total energy E > MGL, the pendulum will continuously rotate over the top.
- Explains that without energy loss, the system behaves like a ball rolling over a hill.
- Distinguishes between the linearized period (simple harmonic motion) and the actual period.
- Sets up the integral for the period by rearranging the energy conservation equation.
- The exact period involves an elliptic integral, not a simple 2*pi/omega.
- Starts with the energy equation and solves for theta_dot squared.
- Rearranges to get dt = d(theta) / sqrt(...), leading to an integral for time.
- The period is found by integrating over a full cycle (e.g., from -theta_0 to theta_0).
- Utilizes the symmetry of the potential energy to simplify the period integral.
- The period can be calculated as 4 times the integral from 0 to theta_0.
- Factors out sqrt(L/G) from the integral, leaving a dimensionless integral dependent on theta_0.
- The integral part is dimensionless, confirming the T ~ sqrt(L/G) scaling.
- The factor of 4 and the integral define the precise coefficient for the period.
- Notes that the integral is an elliptic integral, often requiring numerical computation.
- Discusses the physical meaning of the tension T in the pendulum rod.
- If T becomes negative, it indicates the rod is pushing rather than pulling.
- This signifies the rod becoming slack, analogous to a rope or snowboarder leaving a surface.
- Sets up the problem of a mass constrained to a surface under gravity.
- Defines the normal reaction force (n) and gravity (G).
- Assumes a smooth surface, meaning no friction and the normal force is perpendicular to the surface.
- States that the normal force (n) must be orthogonal to the surface.
- The velocity vector (r_dot) is always tangent to the surface.
- The condition n dot r_dot = 0 expresses this orthogonality.
- For a surface of revolution, the normal force has no component in the circumferential (e_theta) direction.
- This means N dot e_theta = 0 due to axial symmetry.
- This symmetry simplifies the analysis of forces.
- Highlights two approaches: Newton's laws or energy domain.
- Energy conservation applies for conservative systems (gravity, smooth constraints).
- The system is 2D (on the surface), not 3D, requiring reduction of variables.
- Dots Newton's second law with the e_theta unit vector.
- Uses the fact that N dot e_theta = 0 for surfaces of revolution.
- Derives d/dt (r^2 * theta_dot) = 0, leading to conservation of r^2 * theta_dot = H.
- Confirms that the z-component of angular momentum (L0_z) is conserved for motion on a surface of revolution.
- L0_z = M * r^2 * theta_dot = M * H.
- This conservation arises from the axial symmetry of the system.
- Introduces a tangent vector (tau) to the curve of revolution (z = H(r)).
- Dots Newton's second law with tau to eliminate the unknown normal force N.
- Derives a complex equation involving r, theta_dot, z, and H'(r).
- Uses the relationship z = H(r) and its derivatives (z_dot, z_double_dot) to eliminate z.
- Substitutes H and its derivatives into the equation derived from tau dot Newton's law.
- Results in a single, albeit messy, second-order ODE for r(t).
- Considers a particle projected horizontally with speed V from height Z=a in a parabolic bowl.
- Asks if the marble reaches the bottom (Z=0), considering no drag.
- Uses conservation of energy (1/2 M |r_dot|^2 + MgZ = E) and angular momentum (r^2 theta_dot = H).
- Determines initial conditions: Z(0)=a, R(0)=2a, R(0)theta_dot(0)=V.
- Calculates H = R(0) * R(0)theta_dot(0) = 2aV.
- Calculates total energy E = 1/2 M (H^2 / R(0)^2) + MgZ(0) = M V^2 / 2 + Mga.
- Rewrites the energy equation in a form resembling T + V = constant.
- Defines a 'curly T' (pseudo-kinetic) and 'curly V' (effective potential) that depend on Z.
- Analyzes the shape of the effective potential V(Z) to determine allowed motion.
Summary, takeaways, and chapters were generated by AI from the video's transcript and may contain errors. The video belongs to its creator, Oxford Mathematics.